Convert A Binary String to A Decimal Number

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The tech resource your business needs. These paths are used frequently in a variety of front-end development and QA automation tasks. One of a set of tools we're offering as a way of saying thank you for being a part of the community. Are you are experiencing 4 convert binary to string vbnet similar issue? Get a personalized answer when you ask a related question.

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View April's Free Course. I need a solution. Sign up today x. NET I need to decode a fixed length header on a packet of compressed data.

The header is always 32 bytes. This is followed by four binary 4-byte integer values for the data packet type, sequence number for making sure we're not missing packetsthe compressed size, and the decompressed size. Here is my code: FileStream inFil e, System.

Read 4 convert binary to string vbnet, 0, b. Use the BitConverter class: Also, there is a problem with how you are reading the file. You are right in that you should call the Read method as long as it returns a value larger than zero, but you have to read the data into the array at different positions, otherwise the second block will overwrite the first.

As you don't have any check for how much data you read, your current code will read the entire file, so you don't get the header at all, but some arbitrary data at the end of the file.

This code will read binary data from the file until you reach the end of the file or the size of the array: Read b, pos, b. Length The pos variable will contain the amount of data read. You should 4 convert binary to string vbnet this value so that you are sure that you really got the amount of data that you expect.

And, you are declaring the array to 34 bytes, not 32 bytes. When you declare an array you give the index of the last item, so for a 32 byte array the last index is Dim b 31 As Byte. There is no binary strings in.

NET are unicode, so each character is a 16 bit value. To handle binary data 4 convert binary to string vbnet use byte arrays, not strings. If you decode the data into a string, the values will change, so some character values will be different than the byte values they were decoded from. Also, UTF8 uses more than one byte to 4 convert binary to string vbnet some characters, so if you decode an array of 32 bytes, you don't always get a 32 character string.

GetBytes b, 0, Hi and Thanks GreenGhost; I incorporated your changes and have the following to report: GetBytes b, 0, 16 " I get a compile error: Value of type '1-dimensional array of Byte' cannot be converted to '1-dimensional array of Char' because 'Byte' is not derived from 'Char' Using bitconverter didn't error out but I'm not getting the results that I am looking for.

I am going to try to attach a sample binary header file and a txt file with the expected results for you to have a look at. Here is the Sub incorporating your suggestions: To get the string, it should of course be the GetString method, not the 4 convert binary to string vbnet method.

GetString b0, 16 My mistake I was actually looking at the documentation for GetString and eventhough wrote GetBytes The binary data that you are reading have the integers stored in big endian format Motorola rather than little endian format Intel. So you have to swap the bytes around before converting them: ToInt32 to call ConvertToInt instead.

GreenGhost - Thanks very much for your help! I haven't had to do this type of conversion before and you got me squared away very quickly Question has a verified solution. Sign up with Google. Sign up with LinkedIn. 4 convert binary to string vbnet up with Facebook. I would like to receive news, updates and offers from Experts Exchange.

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How do you convert a number to a binary literal in Visual Basic. How do you convert a binary literal to a number in Visual Basic. A suggested answer is given in the following simple windows form program. This page has 4 sections:.

This program will convert a number from 0 - into a text representation of the binary equivalent a binary literal. For example, entering will produce The program will also convert a binary literal to its equivalent decimal number.

If you enter it will display The functions that do the conversion are: There are two versions of the code presented. The first contains extensive comments that hopefully explain what is going on and how the code works. The second version is the same except the comments have been removed for brevity. Any recent version - should work. Feel free to change the text of the labels and buttons to whatever you want. As you create the controls it can be a good idea to give the controls more meaningful names.

If you do this remember to changes the control names in the code. Simply copy and paste it from below. The first version of the code is heavily commented below is a version without the comments. This is the binary literal. The function then works through the string one character at a time taking the character at position i in the string i is the loop counter. It converts each character into a number - an integer 1 or Bitshifting means that all the digits in the byte are moved or shifted one place to the left.

The code in red above does this. Lets take the literal 1. The function will take the '1' at the far right and convert it to a number 1. This number 1 is then stored in a variable of type Byte. The byte for 1 contains the bits - As the is converted to a byte is is 'bitshifted' by Math. First time through the loop the counter is 7 so Math. It is bitshifted by 0 places - it doesn't move this time! The byte still contains The tempByte which is currently 0 is then OR 'd with this The second time through the loop the counter, i, is 6 and its inverse is 1.

The function therefore takes the 6th character from the literal 0 1. The 0 produces a byte containing This is shifted by 1 place to the left which makes no difference! This is then OR'd with the tempByte which is now The third time through the loop the counter, i, is 5 and its inverse is 2. The function therefore takes the 5th character of from the literal 1 0 1. The 1 produces a byte containing This is shifted 2 places to the left and is now This is then Or'd with the tempByte which is now The function continues taking each character in turn, converting it to a 1 or 0 and ORing this with the tempByte.

In essence it is simply putting a 1 or 0 in the same place in the tempByte as a "1" or "0" appears in the binary literal. The tempByte in our example ends up being 1. But this is exactly what we started off with you might say. Well yes but we started with a string of 8 "1"s or "0"s and have ended up with 8 bits of either 1 or 0. Visual Basic sees bytes as numbers. We can now display the byte as number in this case This number is converted to a byte and stored in byteToConvert.

The functions then loops 8 times. The loop counter counts down from 7 to 0. Each time through the loop the a byte containing the bits the decimal number 1 is bit shifted moved to the left by the same value as the loop counter i.

It is if the bit at postion i in the byteToConvert is a 1. It is if the bit at position i of the byteToConvert is a 0. Each time through the loop tempByte is tested and if it contains a "1" is appended to a text string. If tempByte contains a "0" is appended to the text string result. At the end of the loop a text string of 8 characters is created. It has "1"s and "0"s in the same position as the 1s and 0s in the byte we started with.

For example lets take the number Convert it to a byte and the bits in that byte are: This is our byteToConvert. Lets follow it through our function loop:. They can, however, be very useful when you wish to manipulte the bits within a byte. To convert between numbers and binary literals or to use the bits as flags.

I created the functions above to help me process numbers and binary literals before sending and receiving them via a serial port to various PIC and Arduino microcontroller projects I'm working on. Being able to convert between numbers and literals is very useful when you want to control the exact 1's and 0's you send. Bitwise operation - Wikipedia page on Bitwise operations. Please feel free to use this code in your programs for non commercial use only.

Please acknowledge any uses. This page has 4 sections: What the program does - Brief introduction Bytes and Bits program - Full code for the program Short non-commented version of the code - Same code but without the comments How it works - explanation of the two main functions What the program does This program will convert a number from 0 - into a text representation of the binary equivalent a binary literal.

Object, ByVal e As System. Text Then ' It does Text Else ' It doen't Show "Enter a valid number" TextBox1. Focus Exit Sub End If 'Is the number within an acceptable range 'in this case 0 - as we are only 'using 8 bit bytes eg. Show "Enter a number between 0 and " TextBox1.

Length 'Check to make sure they have only entered '8 characters If binStringLength 8 Then 'less or more than 8 characters 'warn the user and exit the sub MessageBox. Warn user and exit sub MessageBox.